Piano Player Playing Cards

Deck of cards by Xu Yu Juan
Email me when new stock arrives
Free shipping Free shipping to USA
Add to wishlist

Get 113 VI Points for this purchase.

Piano Player Playing Cards

11.25 usd

Deck of cards by Xu Yu Juan (11.25)

Out of stock. Email me when new stock arrives.

Limited Edition Release.

The black and white keys are arranged in an orderly manner, seemingly simple, but can create countless beautiful melodies: The Piano - King of the musical instruments, the embodiment of the art of music!

Inspired by the elegant look of the piano, the deck is almost like a miniature version of it. With its ingenious design, and classical charm, the lines and notes are perfectly harmonized with the deck.

Two versions available: Two-Key and Three-Key

Both the Piano Player Two-Key Edition Playing Cards and Piano Player Three-Key Edition Playing Cards are printed by Make Playing Cards and limited to 2,500 decks each.

Add to cart
 

Customer reviews for Piano Player Playing Cards

Reviewer

Breanna

I’m obsessed with the design on these cards! They really are elegant and it’s a design I’ve never seen before!! They also do really well when shuffling and magic. Another thing about these cards is they look so professional when doing magic or playing games.

 
Reviewer

John

Love these cards. They feel great and have both a musical as well as magical touch. There are no double backers, however if you’re looking to add a personalized feel to your performances these decks are great!
-Fun two way treble clef design with grand
-composer joker cards
(There is no tuck case seal)

 

Community questions about Piano Player Playing Cards

Have a question about this product? It's possible others do too. Ask here and other Vanishing Inc. Magic customers will be able to respond with assistance! Alternatively, email us and we can help too.

  • Kyle asks: Are there any double backers or blank cards in the deck?

    • 1. SGKYDUYEN answers: As far as I know, this deck does not come with a double backer
    Post an answer to this question
Ask a question